Posted by Gaby on Sunday, December 7, 2008 at 3:12pm.
Without looking, a player chooses one marble from each bucket in the Red and Blue game. If the player gets a red and blue marble they win. Each player pays $1.00 to win and if wins gets $3.00. One bucket contains 1blue,1green,1red,1yellow. The second bucket contains 1red,1green,1yellow.
Suppose the game is played 36 times, how much money can the school expect to collect?

Math  Michael, Sunday, December 7, 2008 at 3:19pm
wll...they need 2 things to happen to win
1) a blue marble from the first bucket (1 in 4 chance)
2) a red marble from the 2nd (1 in 3 chance)
so the chance for a win is (1/4) times (1/3) or (1/12)
if the game is played 36 times, then statistically 3 poeple should win
(36 X 1/12 = 3)
now if playyed 36 times the school will collect $36
if 3 won they will loose (3X$3 = $9)
so the net sum is 369 or $27

Math  Gaby, Sunday, December 7, 2008 at 3:35pm
Ok I get it now!!!! Thank you so much!
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