Friday

December 19, 2014

December 19, 2014

Posted by **jessica** on Sunday, December 7, 2008 at 11:41am.

(3x+5)^2+8=0

also

6-9=12 divided by y+5 y-5 y^2-25

- algebra -
**bobpursley**, Sunday, December 7, 2008 at 12:10pmOn the first, two ways...

Let me do the easiest. Notice that the first term for real x will always be positive, and the second term is positive, the sum is zero. So there are no real x.

(3x+5)^2=-8

take the square root of each side..

3x+5=sqrt (-8)= 2i sqrt2

then solve for x. It will be a complex number.

Second

Multiply both sides by (y^2-25)

6(y-5)-9(y+5)=12

multiply out, gather terms and solve for y.

- algebra -
**jessica**, Sunday, December 7, 2008 at 12:39pmThank you very much

**Answer this Question**

**Related Questions**

Algebra - I am really having problems with monomials: Please help! Simplify: 4x^...

math - I must simplify this equation and am having a hard time (5+2a+3a)-(a2+a-6...

Algebra - x^2+6x-44/x+9 X squared plus six X minus 44 divided by X+9. Having a ...

Math - help please anyone? i'm having a hard time solvig these problems LOGIC ...

Pre-algebra - So i am having a hard time with special right triangles and wanted...

algebra 1 help - I am having a hard time understanding these problems would some...

college algebra--please help - Form a polynomial f(x) with real coefficients ...

Algebra 1 - I'm having a hard time understanding distance rate and time word ...

Algebra - I have several of these problems and am having trouble getting the ...

Math - I have a question I am having a hard time with..... 2 more than 6 times a...