Sunday

March 29, 2015

March 29, 2015

Posted by **Steve** on Sunday, December 7, 2008 at 1:22am.

I got the V0 to be 2.43 from mhg = 1/2mv^2 but after setting up M1V1=M1V1' + M2V2' i dont know what to do

- Physics -
**drwls**, Sunday, December 7, 2008 at 1:34amThe speed of the sliding cube at impact is V = sqrt(2gH) = 2.42 m/s

Next you have to figure out the velocities of the sliding cube (mass M) and the impacted cube (Mass M/2), after impact. You need to write equations of both momentum and kinetic energy conservation. You will find, if you do it right, that the smaller cube travels at 4V/3 and the larger cube at V/3.

Finally, use those horizontal velocities and the height of the table to predict where they land.

**Answer this Question**

**Related Questions**

physics - A small block is released from rest at the top of a frictionless ...

physics - A small block is released from rest at the top of a frictionless ...

physics - A frictionless incline is 5.00 m long (the distance from the top of ...

Physics - A mass of 14 kg is moving at a speed of 39 m/s at the bottom of ...

Physics - A mass of 18 kg is being pushed up a frictionless incline with a ...

Physics - A mass of 18 kg is being pushed up a frictionless incline with a ...

Physics - A mass of 18 kg is being pushed up a frictionless incline with a ...

Physics 1 - A mass of 11 kg is being pushed up a frictionless incline with a ...

physics - A small block with mass 0.308 kg is sliding down a frictionless ramp ...

Physics - A block of mass = 2.20 kg slides down a 30.0 deg incline which is 3.60...