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November 22, 2014

November 22, 2014

Posted by **Steve** on Sunday, December 7, 2008 at 1:22am.

I got the V0 to be 2.43 from mhg = 1/2mv^2 but after setting up M1V1=M1V1' + M2V2' i dont know what to do

- Physics -
**drwls**, Sunday, December 7, 2008 at 1:34amThe speed of the sliding cube at impact is V = sqrt(2gH) = 2.42 m/s

Next you have to figure out the velocities of the sliding cube (mass M) and the impacted cube (Mass M/2), after impact. You need to write equations of both momentum and kinetic energy conservation. You will find, if you do it right, that the smaller cube travels at 4V/3 and the larger cube at V/3.

Finally, use those horizontal velocities and the height of the table to predict where they land.

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