posted by cookie monster on .
a 2.0 kg crate is incline at 60degrees and is held in equilibrium by a horizontal force..
what is the magnitude of this horizontal force? (disregard friction)
The inclines applies a force M g cos 60 = M g/2 to the crate, in a direction normal to the incline surface. The horizontal component of that force equals the force that keeps it in equilibrium.
I will leave you to compute that
is the horizontal force the same as the normal force?
No. The normal force is perpendicular to the incline surface