Posted by **Anne** on Saturday, December 6, 2008 at 8:45pm.

a 15g bullet strikes and becomes embedded in a 1.1kg block of wood placed on a surface in front of the gun. if the coefficient of kinetic friction between the block and the surface is 0.25 and the impact drives the block a distance of 95m before it comes to rest, what was the muzzle speed of the bullet?

What i did was F = umg = 2.73 = ma. so a = 2.45.

then i used Vf^2 = Vo^2 + 2a(deltaX) so Vo = 6.8.

then M1V1 = (M1+M2)(V1)'

But my V1 is 507 m/s while the answer is 515 m/s.

Where did i go wrong?

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