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December 26, 2014

December 26, 2014

Posted by **Melly** on Saturday, December 6, 2008 at 5:31pm.

lim x-->3 (x^3-27)

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(x^2-9)

- Precalculus -
**Melly**, Saturday, December 6, 2008 at 5:33pmIt might look better this way...

lim x-->3 (x^3 -27)/(x^2 -9)

- Precalculus -
**Reiny**, Saturday, December 6, 2008 at 6:00pmit factors

lim x-->3 (x^3 -27)/(x^2 -9) ax x--->3

= lim [(x-3)(x^2 + 3x + 9)]/[(x+3)(x-3)]

= lim (x^2 + 3x + 9)/(x+3)

= (9+9+9)/(3+3)

= 9/2

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