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Precalculus

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How would I find the limit of (if it exists):

lim x-->3 (x^3-27)
--------
(x^2-9)

  • Precalculus - ,

    It might look better this way...

    lim x-->3 (x^3 -27)/(x^2 -9)

  • Precalculus - ,

    it factors

    lim x-->3 (x^3 -27)/(x^2 -9) ax x--->3
    = lim [(x-3)(x^2 + 3x + 9)]/[(x+3)(x-3)]
    = lim (x^2 + 3x + 9)/(x+3)
    = (9+9+9)/(3+3)
    = 9/2

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