Posted by Confused on .
What is The solution set of 2k^2=21k49 ?

math 
Reiny,
this an be arranged to the quadratic
2k^2  21k + 49 = 0
(2k7)(k7) = 0
k = 7/2 or k7 
math 
Confused,
Thanks! how do u determine that they are both 7 though? Doesn't it have to equal 21? or doesn't that 21 matter?

math 
Reiny,
why don't you expand (2k7)(k7 to see what you get?

math 
Brenden,
oh it makes sense now thanks!

math 
Kyle Thompson,
what is Expand:4(2m  7x + 9)