the two parallel bases of a trapezoid are 5inches and 6 inches long. the altitude of the trapezoid is 4inches. what is the area of the trapeziod?
i got 15
Well the area will be the sum of the area of a rectangle and either 1 or 2 triangles depending on what way you draw it.
The area of the rectangle will be height*shorter length = 4*5 = 20
The area of the triangle will be
(1/2)*base*height
base of triangle in this case =
longer length - shorter length = 6-5 = 1
Therefore area = (1/2)*1*4 = 2
So the total area = 20 + 2 = 22
You are both wrong.
The area of a trapezoid = sum of parallel sides/2* height
= (5+6)/2*6 = 33
To find the area of a trapezoid, you can use the formula:
Area = (a + b) * h / 2
Where:
- a and b are the lengths of the parallel bases
- h is the altitude (height) of the trapezoid
In this case, the lengths of the parallel bases are 5 inches and 6 inches, and the altitude is 4 inches.
Plugging these values into the formula, we have:
Area = (5 + 6) * 4 / 2
Area = 11 * 4 / 2
Area = 44 / 2
Area = 22
So, the area of the trapezoid is 22 square inches. Therefore, your answer of 15 is incorrect.