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March 25, 2017

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2. a 755N diver drops from a board 10.0 m above the water's surface. Find the divers speed 5.00 m above the water's surface. then find the diver's speed just before striking the water.

3. if the diver in item 2 leaves the board with an initial upward speed of 2.00 m/s find the divers speed when striking the water.

i don't know how to start these two at all...i don't need the answer i just need the formulas that i use for it...i don't understand which ones to use.. plz help

  • physics!-concervation of energy equations - ,

    you can use:

    (vf)^2 = (v0)^ + 2as

    where vf is "final velocity"
    v0 is "initial velocity"

    a is acceleration
    and s is distance

  • physics!-concervation of energy equations - ,

    is the initial velocity squared? it has an ^ ???

  • physics!-concervation of energy equations - ,

    yes, if the initial velocity is squred

  • physics!-concervation of energy equations - ,

    wait...if this is conservation of energy, better to use:

    convert the potential energy into kinetic energy! (sorry).

    potential energy is mgh, and kinetic enery is (1/2)m*v^2

  • physics!-concervation of energy equations - ,

    lol wat do i do with that...do i put it equal to eachother

  • physics!-concervation of energy equations - ,

    So, it depends on what you're currently studying. If you're studying equations of motion, then use my first suggestion, but if you're studying conservation of energy, use mgh = (1/2)m*v^2.

    The m's cancel out:
    So, gh = v^2/2. You can solve for v, the velocity, by setting h, the height, first to 5, and then to 10.

  • oxgdkiwnp yqbmurxdt - ,

    zklsvhmiy uxjarfh rvglzy vmai guhv wjkaqem gelfhdnt

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