Posted by gaby on Thursday, December 4, 2008 at 9:33pm.
you can use:
(vf)^2 = (v0)^ + 2as
where vf is "final velocity"
v0 is "initial velocity"
a is acceleration
and s is distance
wait...if this is conservation of energy, better to use:
convert the potential energy into kinetic energy! (sorry).
potential energy is mgh, and kinetic enery is (1/2)m*v^2
lol wat do i do with that...do i put it equal to eachother
So, it depends on what you're currently studying. If you're studying equations of motion, then use my first suggestion, but if you're studying conservation of energy, use mgh = (1/2)m*v^2.
The m's cancel out:
So, gh = v^2/2. You can solve for v, the velocity, by setting h, the height, first to 5, and then to 10.
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