Posted by gaby on .
2. a 755N diver drops from a board 10.0 m above the water's surface. Find the divers speed 5.00 m above the water's surface. then find the diver's speed just before striking the water.
3. if the diver in item 2 leaves the board with an initial upward speed of 2.00 m/s find the divers speed when striking the water.
i don't know how to start these two at all...i don't need the answer i just need the formulas that i use for it...i don't understand which ones to use.. plz help

physics!concervation of energy equations 
DanH,
you can use:
(vf)^2 = (v0)^ + 2as
where vf is "final velocity"
v0 is "initial velocity"
a is acceleration
and s is distance 
physics!concervation of energy equations 
gaby,
is the initial velocity squared? it has an ^ ???

physics!concervation of energy equations 
DanH,
yes, if the initial velocity is squred

physics!concervation of energy equations 
DanH,
wait...if this is conservation of energy, better to use:
convert the potential energy into kinetic energy! (sorry).
potential energy is mgh, and kinetic enery is (1/2)m*v^2 
physics!concervation of energy equations 
gaby,
lol wat do i do with that...do i put it equal to eachother

physics!concervation of energy equations 
DanH,
So, it depends on what you're currently studying. If you're studying equations of motion, then use my first suggestion, but if you're studying conservation of energy, use mgh = (1/2)m*v^2.
The m's cancel out:
So, gh = v^2/2. You can solve for v, the velocity, by setting h, the height, first to 5, and then to 10. 
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