Posted by **gaby** on Thursday, December 4, 2008 at 9:03pm.

2. a 755N diver drops from a board 10.0 m above the water's surface. Find the divers speed 5.00 m above the water's surface. then find the diver's speed just before striking the water.

3. if the diver in item 2 leaves the board with an initial upward speed of 2.00 m/s find the divers speed when striking the water.

i dont know how to start these two at all...i dont need the answer i just need the formulas that i use for it...i dont understand which ones to use.. plz help

- physics -
**drwls**, Friday, December 5, 2008 at 6:54am
Use a conservation of energy approach for both problems. The CHANGE in (1/2)M V^2 equals the change in M g H.

That means the change in V^2 equals 2 g times the change in height above the water, H.

For the second problem, the water is 10 m below but he had a speed of V^2 = 2 m/s at the start.

Vfinal^2 = Vinitial^2 + 2 g h

= 4.0 + 2*9.8*10 = 200

V = 10 m/s

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