Wednesday

April 16, 2014

April 16, 2014

Posted by **gaby** on Thursday, December 4, 2008 at 9:03pm.

3. if the diver in item 2 leaves the board with an initial upward speed of 2.00 m/s find the divers speed when striking the water.

i dont know how to start these two at all...i dont need the answer i just need the formulas that i use for it...i dont understand which ones to use.. plz help

- physics -
**drwls**, Friday, December 5, 2008 at 6:54amUse a conservation of energy approach for both problems. The CHANGE in (1/2)M V^2 equals the change in M g H.

That means the change in V^2 equals 2 g times the change in height above the water, H.

For the second problem, the water is 10 m below but he had a speed of V^2 = 2 m/s at the start.

Vfinal^2 = Vinitial^2 + 2 g h

= 4.0 + 2*9.8*10 = 200

V = 10 m/s

**Related Questions**

physics!-concervation of energy equations - 2. a 755N diver drops from a board ...

physics - A 751 N diver drops from a board 9.10 m above the water’s surface. The...

physics - A diver of mass m drops from a board 12 m above the water surface. ...

john tyler - a 751 diver drops from a board 9.10 m above the water's surface. ...

physics - A lowly high diver pushes off horizontally with a speed of 2.75 m/s ...

physics - A 48.0 kg diver steps off a 10.0 m high diving board and drops ...

Math - The path of a cliff diver as he dives into a lake is given by the ...

Physics - A 50.0 kg diver steps off a diving board and drops straight down into ...

PHYSICS - A 58.3 kg diver steps o a diving board and drops straight down into ...

physics - A 42.1 kg diver steps off a diving board and drops straight down into ...