Posted by **Maxie** on Thursday, December 4, 2008 at 8:09pm.

The length of a rectangle is 8 cm greater than its width. Find the dimensions of the rectangle if its area is 105 cm.

How do I solve?

- Math -
**CianĂ¡n**, Thursday, December 4, 2008 at 8:34pm
Area = Length*Width

Information you are given:

Area = 105cm^2

and

Length = width + 8

therefore:

105 = (width + 8)*width

105 = width^2 + 8*width

105 = w^2 + 8w

rearranging we get a quadratic:

w^2 + 8w - 105 = 0

w^2 - 7w +15w - 105 = 0

w(w - 7) + 15(w - 7) = 0

(w - 7)(w + 15) = 0

The two possible solutions are

width = 7 or width = -15

Well, the width must be a positive measurement so we take the width = 7

So the answer is:

Width = 7

Length = 7 + 8 = 15

Ok,

Hope that helps

- Math -
**Anonymous**, Sunday, May 29, 2016 at 7:16pm
The width of a rectangle is 34 units less than its length period if x is the rectangle's length, then it's area is?

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