Posted by **Maxie** on Thursday, December 4, 2008 at 8:09pm.

The length of a rectangle is 8 cm greater than its width. Find the dimensions of the rectangle if its area is 105 cm.

How do I solve?

- Math -
**Cianán**, Thursday, December 4, 2008 at 8:34pm
Area = Length*Width

Information you are given:

Area = 105cm^2

and

Length = width + 8

therefore:

105 = (width + 8)*width

105 = width^2 + 8*width

105 = w^2 + 8w

rearranging we get a quadratic:

w^2 + 8w - 105 = 0

w^2 - 7w +15w - 105 = 0

w(w - 7) + 15(w - 7) = 0

(w - 7)(w + 15) = 0

The two possible solutions are

width = 7 or width = -15

Well, the width must be a positive measurement so we take the width = 7

So the answer is:

Width = 7

Length = 7 + 8 = 15

Ok,

Hope that helps

## Answer This Question

## Related Questions

- math - a rectangle is twice as long as it is wide. if both of its dimensions are...
- MATH - THE LENGTH OF A RECTANGLE IS 3M MORE THAN 2 TIMES ITS WIDTH. IF THE AREA ...
- algebra , help - Can someone help me set up the equations thanks. Directions: ...
- math - The length of a rectangle is 2 inches longer than the width. The area of ...
- math ,correction - Directions: Solve each of the following problems. Be sure to ...
- math - the length of a rectangle is 1 cm less than twice its width. the area is ...
- math - the length of a rectangle is 3 yds more than twice it width and the area ...
- Algebra/geometry - a rectangle has a width of 4 cm less than it's length. if a ...
- math - The length of a rectangle is 3 m more than double the width, and the ...
- Math - The length of a rectangle is 11 cm more than its width. The area of the ...

More Related Questions