Posted by Maxie on Thursday, December 4, 2008 at 8:09pm.
Area = Length*Width
Information you are given:
Area = 105cm^2
Length = width + 8
105 = (width + 8)*width
105 = width^2 + 8*width
105 = w^2 + 8w
rearranging we get a quadratic:
w^2 + 8w - 105 = 0
w^2 - 7w +15w - 105 = 0
w(w - 7) + 15(w - 7) = 0
(w - 7)(w + 15) = 0
The two possible solutions are
width = 7 or width = -15
Well, the width must be a positive measurement so we take the width = 7
So the answer is:
Width = 7
Length = 7 + 8 = 15
Hope that helps
Algebra/geometry - a rectangle has a width of 4 cm less than it's length. ...
Algebra - A rectangle was 25 cm longer than it was wide. A new rectangle was ...
Math - If the length of a rectangle is (2x-1)cm and its width is (x+3)cm. How do...
algebra , help - Can someone help me set up the equations thanks. Directions: ...
geometry - The width of a rectangle is 6 cm less than its length. If the area of...
math - The width of a rectangle is 6 cm less than the length. A second rectangle...
math - the length of a rectangle is 1 cm less than twice its width. the area is ...
math - The length of a rectangle is 5 cm more than twice the width. The ...
algebra - The length of a rectangle is 6 cm more than four times the width. If ...
math - the length of this rectangle is 3 cm greater than its width ,as ...
For Further Reading