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February 26, 2015

February 26, 2015

Posted by **shay** on Thursday, December 4, 2008 at 6:42pm.

- math -
**drwls**, Thursday, December 4, 2008 at 6:56pmThe number of weeks later would be the lowest common multiple of 4,8,12 and 16.

That number would have to have as prime factors at least four 2's, and one 3. That means the ships return together

2^4 x 3 = ? weeks later.

Assume it is not a leap year

- math -
**shae**, Thursday, December 4, 2008 at 7:08pmso the answer is 48 but how many days was in the year; with leep years

- math -
**drwls**, Thursday, December 4, 2008 at 7:21pmWhat is 48 weeks after Janaury 2?

1953 was not a leap year.

You do the counting. Don't use a 2008 calendar.

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