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December 20, 2014

December 20, 2014

Posted by **Landon** on Thursday, December 4, 2008 at 6:15pm.

4p^2 + 121 = 44p

I seriously don't understand and it's frustrating for me. Please help. (:

- Algebra:quadratic equations -
**alyssa**, Thursday, December 4, 2008 at 6:32pmfirst you subtract the 44p from both sides to get 4p^2 + 121 - 44p = 0. Then you find two factors of 4p^2. They are 2p and 2p(2p x 2p = 4p^2). Then find two factors of 121 that, when multiplied with the 2p, equals 44p. they are 11 and 11(11 x 11 = 121)

Set the quadratic up like this: (2p - 11)(2p - 11). If you multiply this out, it will equal what you started with!

- Algebra:quadratic equations -
**Landon**, Thursday, December 4, 2008 at 6:44pmSo this doesn't involve finding pi and sigma then?

- Algebra:quadratic equations -
**julieth**, Thursday, December 4, 2008 at 7:54pmx^2-8=7x

- Algebra:quadratic equations -

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