Posted by Landon on Thursday, December 4, 2008 at 6:15pm.
first you subtract the 44p from both sides to get 4p^2 + 121 - 44p = 0. Then you find two factors of 4p^2. They are 2p and 2p(2p x 2p = 4p^2). Then find two factors of 121 that, when multiplied with the 2p, equals 44p. they are 11 and 11(11 x 11 = 121)
Set the quadratic up like this: (2p - 11)(2p - 11). If you multiply this out, it will equal what you started with!
So this doesn't involve finding pi and sigma then?
x^2-8=7x
Related Questions
Algebra 2 - please help i seriously dont understand any of these!! solve by ...
algebra - Solve the following equation: k2 + 4k = 0 By factoring and By using ...
algebra 2 - how do you solve quadratic equations by factoring?
Pre algebra - How do I solve Quadratic equations by factoring? (for example how ...
Math (Algebra) - Could someone help to explain to me how factoring is used to ...
Algebra Quadratic Equations - I am trying to define the different appraoches to ...
ALGEBRA - Explain how factoring is used to solve quadratic equations. ...
algebra - Can someone help me explain how factoring is used to solve quadratic ...
algebra - Quadratic equations can be solved by graphing,using the quadratic ...
Algebra 2 - I need to know how to solve quadratic equations by factoring. Can ...
For Further Reading
