Posted by Sandhya on Thursday, December 4, 2008 at 6:05am.
5 mol of an ideal gas is kept at 394◦C in an expansion from 1 L to 5 L .How much work is done by the gas? Answer in units of J.Given: R = 8.31 J/K/mol ,

Thermodynamics  drwls, Thursday, December 4, 2008 at 7:01am
Hmm. An isothermal expansion. The pressure must fall by a factor of 5 during this process. The initial pressure is
P1 = n R T = (5 moles/liter)*0.08206 Liter atm/mole K)* 667 K = 274 atm = 2.77*10^7 N/m^2
P2, the final pressure, is 1/5 of P1
The work done is the integral of P dV. Since PV is constant in an isothermal process, P = P1 V1/V
Work = Integral P1*V1 dV/V
V1=1 to V2=5
= 2.77*10^7 N/m^2 * 10^3 m^3 * ln 5
= 4.46*10^4 Joules
Check my work. The method is more likely to be correct than my calculations
Answer This Question
Related Questions
 physics  A container of volume 0.39 m3 contains 8.7 mol of argon gas at 32&#...
 Physics I  A container of volume 0.71 m3 contains 1 mol of argon gas at 27&#...
 chem  6.01L cylinder contains 1.25 mol of gas A and 4.54 mol of gas B, at a ...
 chem  6.01L cylinder contains 1.25 mol of gas A and 4.54 mol of gas B, at a ...
 physics  An ideal gas is enclosed in a cylinder with a movable piston on top of...
 physics  An ideal gas is enclosed in a cylinder with a movable piston on top of...
 physics  An ideal gas is enclosed in a cylinder with a movable piston on top of...
 thermodynamics and kinetics  One mole of an ideal gas undergoes an isothermal ...
 physics  1.7 mol of an ideal gas which starts at 1.6 atm and 50 o C does 2.0 kJ...
 Physics  A container having a volume of 1 m3 holds 90 mol of helium gas at 176...
More Related Questions