Posted by kim on .
2. A .12 kg ball is moving at 6 m/s when it is hit by a bat, causing it to reverse direction and have a speed of 14 m/s. What is the change in the magnitude of the momentum of the ball?
4. Lonnie pitches a baseball of mass .2 kg. The ball arrives at home plate with a speed of 40 m/s and is batted straight back to Lonnie with a return speed of 60 m/s. If the bat is in contact with the ball for .050 s, what is the impulse experienced by the ball?

physics PLEASE HELP 
drwls,
2. Although the momentum changes by 0.12 kg * [6 (14)m/s]= 2.4 kg m/s, becasue the direction reverses, the MAGNITUDE of the momentum changes only by 0.12 kg*(14  6)m/s = 0.72 kg m/s
4. Compute the momentum change, taking into account the direction change. That will equal the impulse. Divide that by the time interval of contact to get the average force.