Posted by **Mara** on Wednesday, December 3, 2008 at 5:57pm.

A(n) 840-kg dragster accelerates on a race track from rest to 85 km/h in 0.90 seconds.

(a) What is the change in momentum of the dragster?

(b) What is the average force exerted on the dragster?

(c) What exerts that force?

- physics -
**drwls**, Wednesday, December 3, 2008 at 6:02pm
(a) Multiply m by the change in V. Convert the final speed to m/s first.

(b) Average force = (momentum change)/time

(c) The track exerts the force against the tires.

- physics -
**Anonymous1**, Wednesday, December 3, 2008 at 7:00pm
a) If you did not know before, momentum is equal to mass times velocity, p=mv.

The others, "drwls", has explained it well enough for you.

## Answer This Question

## Related Questions

- Physics - A dragster and driver together have mass 929.4 kg. The dragster, ...
- Physics - A dragster and driver together have mass 929.4 kg. The dragster, ...
- physics - An 879-kg (1943 lb) dragster, starting from rest, attains a speed of ...
- Physics - A dragster accelerates from rest for a distance of 450m at 14 m/s^2. A...
- Physics - A dragster accelerates from rest for a distance of 450m at 14 m/s^2. A...
- Physics - A dragster accelerates from rest for a distance of 450m at 14 m/s^2. A...
- Physics - A dragster and driver together have mass 929.4 kg. The dragster, ...
- physics - A 880-kg (1945 lb) dragster, starting from rest, attains a speed of 27...
- Phsyics - An 865 kg (1912 lb) dragster, starting from rest, attains a speed of ...
- physics - An 855 kg dragster accelerates from rest to 120 km/h in 0.90 seconds. ...

More Related Questions