Posted by Mara on Wednesday, December 3, 2008 at 5:57pm.
A(n) 840kg dragster accelerates on a race track from rest to 85 km/h in 0.90 seconds.
(a) What is the change in momentum of the dragster?
(b) What is the average force exerted on the dragster?
(c) What exerts that force?

physics  drwls, Wednesday, December 3, 2008 at 6:02pm
(a) Multiply m by the change in V. Convert the final speed to m/s first.
(b) Average force = (momentum change)/time
(c) The track exerts the force against the tires.

physics  Anonymous1, Wednesday, December 3, 2008 at 7:00pm
a) If you did not know before, momentum is equal to mass times velocity, p=mv.
The others, "drwls", has explained it well enough for you.
Answer This Question
Related Questions
 Physics  A dragster and driver together have mass 929.4 kg. The dragster, ...
 Physics  A dragster and driver together have mass 929.4 kg. The dragster, ...
 Physics  A dragster accelerates from rest for a distance of 450m at 14 m/s^2. A...
 Physics  A dragster accelerates from rest for a distance of 450m at 14 m/s^2. A...
 Physics  A dragster accelerates from rest for a distance of 450m at 14 m/s^2. A...
 Physics  A dragster and driver together have mass 929.4 kg. The dragster, ...
 physics  An 879kg (1943 lb) dragster, starting from rest, attains a speed of ...
 physics  A 880kg (1945 lb) dragster, starting from rest, attains a speed of 27...
 Phsyics  An 865 kg (1912 lb) dragster, starting from rest, attains a speed of ...
 Physics  A dragster and driver together have mass 900.7 kg. The dragster, ...
More Related Questions