how many grams of glucose are required to produce 50mL of 0.1 m solution?

Two definitions:

1)
molality = # mols/kg solvent

2)
# mols = grams/molar mass

From equation 1, you have molality and kg solvent (50 mL has a mass of 0.050 kg). Calculate mols.

From equation 2, you know mols and molar mass, calculate grams.

0.9g glucose

To calculate the grams of glucose required to produce a 0.1 m solution in 50 mL, you need to know the molecular weight of glucose (C6H12O6) and use the formula:

grams = (molarity × volume × molecular weight) / 1000

The molecular weight of glucose is approximately 180.16 g/mol.

Let's plug in the values:

grams = (0.1 mol/L × 50 mL × 180.16 g/mol) / 1000

Calculating this equation will give us the grams of glucose needed.

To determine how many grams of glucose are needed to produce a 50 mL solution with a concentration of 0.1 M, we need to use the formula:

moles = concentration (molarity) × volume (in liters)

First, we need to convert the volume to liters. Since 1 mL is equal to 0.001 liters, we have:
50 mL = 50 × 0.001 L = 0.05 L

Next, let's substitute the values into the formula and solve for moles:
moles = 0.1 M × 0.05 L = 0.005 moles

Now, we need to determine the molar mass of glucose. Glucose has a molar mass of approximately 180.16 g/mol.

Finally, we can calculate the number of grams of glucose needed by multiplying the moles by the molar mass:
grams = moles × molar mass = 0.005 moles × 180.16 g/mol = 0.9008 grams

Therefore, approximately 0.901 grams of glucose are required to produce a 50 mL solution with a concentration of 0.1 M.