Posted by **Mike** on Monday, December 1, 2008 at 10:40pm.

Can some one help me solve this please.

2e^5x = 712

log5 80= the five is little next to the log

and 2logx=log(6x-90)+1

thanks I would really appriciate it if you could help me out

- Math -
**drwls**, Monday, December 1, 2008 at 11:00pm
You need a pocket calculator or function table to get numerical answers.

2e^(5x) = 712

e^(5x) = 356

5x = ln 356 = 5.8749

x = 1.17499

log(5) 80 = x

5^x = 80

x log 5 = log 80 (any base)

x = 2.7227

log [(6x-90)/x^2] = -1

You need to specify the log base. If the log base is 10

[(6x-90)/x^2] = 0.1

If the log base is e, 1/e goes on the right side.

## Answer This Question

## Related Questions

- check! - here is the question: log5(x-4)= log7x solve for x. These are just base...
- math - solve for x without using a calculator 5^(x+1) = 25 i know that x would ...
- Logarithm help - using logarithms to solve exponential equations. 5^1+x = 2^1-x...
- math - Logarithm!!! Select all of the following that are true statements: (a) ...
- Math - h(x) = log (6x+5/7x-4) Find a formula for the inverse function h^-1(x) h...
- Math Help Please - Which of the following expressions is equal to log (x sqrt-y...
- precalc - I don't understand how to do these w/o calc. I tried to write it in a ...
- Math - solve log(7x-3)+2log(5)=2+log(x+3) I've attempted to do this question ...
- Algebra 2 once more - I have more answers that I would like checked. Also, there...
- math retry 2 - 8^x = 16^x+2, x+2 -2=0 8^x =16^x+2, 2 x 8 = 16 log sub 5 (2x+3)=2...

More Related Questions