Posted by Mike on Monday, December 1, 2008 at 10:40pm.
Can some one help me solve this please.
2e^5x = 712
log5 80= the five is little next to the log
and 2logx=log(6x90)+1
thanks I would really appriciate it if you could help me out

Math  drwls, Monday, December 1, 2008 at 11:00pm
You need a pocket calculator or function table to get numerical answers.
2e^(5x) = 712
e^(5x) = 356
5x = ln 356 = 5.8749
x = 1.17499
log(5) 80 = x
5^x = 80
x log 5 = log 80 (any base)
x = 2.7227
log [(6x90)/x^2] = 1
You need to specify the log base. If the log base is 10
[(6x90)/x^2] = 0.1
If the log base is e, 1/e goes on the right side.
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