Posted by **Mike** on Monday, December 1, 2008 at 10:40pm.

Can some one help me solve this please.

2e^5x = 712

log5 80= the five is little next to the log

and 2logx=log(6x-90)+1

thanks I would really appriciate it if you could help me out

- Math -
**drwls**, Monday, December 1, 2008 at 11:00pm
You need a pocket calculator or function table to get numerical answers.

2e^(5x) = 712

e^(5x) = 356

5x = ln 356 = 5.8749

x = 1.17499

log(5) 80 = x

5^x = 80

x log 5 = log 80 (any base)

x = 2.7227

log [(6x-90)/x^2] = -1

You need to specify the log base. If the log base is 10

[(6x-90)/x^2] = 0.1

If the log base is e, 1/e goes on the right side.

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