Posted by Claudia C. on Monday, December 1, 2008 at 7:56pm.
If the method is not convenient then you should not use.
The factorization is of the form
A (x + p1 y) (x + p2 y)
with A = 56.
If you equate the polynomial to zero and solve for x, the solutions are:
x = -p1 y and x = -p2 y
So, we substitute x = -p y in the polynomial and equate it to zero:
(56 p^2 + 53 p + 12) y^2 = 0
We know that if p = p1 or p2, this will be zero for nonzero y.
So, p1 and p2 are the solutions of the equation:
56 p^2 + 53 p + 12 = 0
p = (-53 +-11)/(2*56)
Related Questions
further mathematics - The roots of the eqn, x^4 + px^3 + qx^2 + rx + s = 0 where...
Maths - Express the sum using summation notation: 1 - 1/2 + 1/3 - 1/4 + 1/5...
Maths - Express the sum using summation notation: 1 - 1/2 + 1/3 - 1/4 + 1/5...
Maths - Express the sum using summation notation: 1 - 1/2 + 1/3 - 1/4 + 1/5...
Algebra - find the indicated sum not sure how to type the sigma sign, but here ...
Engineering Materials - Using mechanics of materials principles (ie. equations ...
Statistics - Let X1,...,Xn be a sample from the N(0, sigma^2). 1) Find the ...
Math - If Σ 1/k^2 from k=1 to infinity = pi^2/6 Use that to show that...
Calculus - The problem with these two questions is that I cannot determine the a...
math - which of the following sums is larger and by how much? 1. 7 over Sigma 15...
For Further Reading