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November 23, 2014

November 23, 2014

Posted by **Claudia C.** on Monday, December 1, 2008 at 7:56pm.

Let's say the problem is this:

56x² - 53xy + 12y²

The pi = 672 = (-____)(-_____)

and the sigma = -53 = (-__) + (-___)

How would you solve the problem?

- Math. -
**Count Iblis**, Monday, December 1, 2008 at 8:38pmIf the method is not convenient then you should not use.

The factorization is of the form

A (x + p1 y) (x + p2 y)

with A = 56.

If you equate the polynomial to zero and solve for x, the solutions are:

x = -p1 y and x = -p2 y

So, we substitute x = -p y in the polynomial and equate it to zero:

(56 p^2 + 53 p + 12) y^2 = 0

We know that if p = p1 or p2, this will be zero for nonzero y.

So, p1 and p2 are the solutions of the equation:

56 p^2 + 53 p + 12 = 0

p = (-53 +-11)/(2*56)

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