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March 30, 2017

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are these correct? and simplifeid correctly?

ax2b/6 x 4/5a = 4ab/15a


xy^2/7 x 7x^2/y = xy^2


3/17rs x 17s^2/4r = 51s/68r^2


2v/3u x 4/6vu = 4/9u^2


31m^2n/41 x 21/mn x 2n^2/3m = 1302n^n 123


3tr/s x 2rt/s^2 = 6t^2r^2/s^3

  • algebra - ,

    Use * for multiplicatrion when you also have x symbols present

    a * 2b/6 * 4/(5a) = 8 b/5
    (I assumed the "5a" was the denominator)

    (xy^2)/7 * (7x^2)/y = x^3y

    Try the others again. You aren't doing it right.

  • algebra - ,

    for the second one wouldnt it just be x^3

  • algebra - ,

    No. You have a y^2 in the numerator and a y in the denominator. They do not cancel out

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