Posted by **ronda** on Monday, December 1, 2008 at 7:48pm.

are these correct? and simplifeid correctly?

ax2b/6 x 4/5a = 4ab/15a

xy^2/7 x 7x^2/y = xy^2

3/17rs x 17s^2/4r = 51s/68r^2

2v/3u x 4/6vu = 4/9u^2

31m^2n/41 x 21/mn x 2n^2/3m = 1302n^n 123

3tr/s x 2rt/s^2 = 6t^2r^2/s^3

- algebra -
**drwls**, Monday, December 1, 2008 at 8:07pm
Use * for multiplicatrion when you also have x symbols present

a * 2b/6 * 4/(5a) = 8 b/5

(I assumed the "5a" was the denominator)

(xy^2)/7 * (7x^2)/y = x^3y

Try the others again. You aren't doing it right.

- algebra -
**ronda**, Monday, December 1, 2008 at 9:31pm
for the second one wouldnt it just be x^3

- algebra -
**drwls**, Monday, December 1, 2008 at 11:04pm
No. You have a y^2 in the numerator and a y in the denominator. They do not cancel out

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