Homework Help: College Algebra Word Problem

Posted by Jenny on Monday, December 1, 2008 at 6:48pm.

A rectangular dog pen is to be made to enclose an area of 625 sq. ft. The pen is to be divided into 2 equal sections by a section of the fence. Find the dimensions of the pen that will require the least amount of fencing material.

Thank you!

College Algebra Word Problem - bobpursley, Monday, December 1, 2008 at 7:07pm
Calculus I assume?

Length*Width= 625
fencelenght= 2L + 3W

W= 625/L

fencelength= 2L+ 3*625/L
d fl/dl= 0=2 -3*625/L^2
or L= sqrt (3/2 * 625)
and W= 625/sqrt (3/2 625)

Now, if you are in algebra, I dont see any way of working this except graphing
fencelength=2L -325/L and looking for the minimum.

Answer this Question

Related Questions

College Algebra - A rectangular dog pen is to be made to enclose an area of 144 ...
math - A rectangular dog pen is to be sectioned off into two seperate areas and ...
Math - A rectangular dog pen is to be constructed using a barn wall as one side ...
math - a farmer has enough fencing to build 40 feet of fence. He wishes to build...
calculus optimization problem - A farmer has 460 feet of fencing with which to ...
algebra - Ian wants to build a rectangular pen for his animals. One side of the ...
geometry - Polly decides to use a wall of the house as one sideof the ...
math - A farmer will make a rectangular pen with 100 feet of fence using pasrt ...
algebra - A man wants to build a rectangular pen in which to keep his dog. If he...
Algebra 2 - One hundred feet of fencing is available to make a rectangular dog ...

For Further Reading

First Name:
School Subject:
Answer: