Posted by **Jenny** on Monday, December 1, 2008 at 6:48pm.

A rectangular dog pen is to be made to enclose an area of 625 sq. ft. The pen is to be divided into 2 equal sections by a section of the fence. Find the dimensions of the pen that will require the least amount of fencing material.

Thank you!

- College Algebra Word Problem -
**bobpursley**, Monday, December 1, 2008 at 7:07pm
Calculus I assume?

Length*Width= 625

fencelenght= 2L + 3W

W= 625/L

fencelength= 2L+ 3*625/L

d fl/dl= 0=2 -3*625/L^2

or L= sqrt (3/2 * 625)

and W= 625/sqrt (3/2 625)

Now, if you are in algebra, I dont see any way of working this except graphing

fencelength=2L -325/L and looking for the minimum.

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