College Algebra Word Problem
posted by Jenny on .
A rectangular dog pen is to be made to enclose an area of 625 sq. ft. The pen is to be divided into 2 equal sections by a section of the fence. Find the dimensions of the pen that will require the least amount of fencing material.
Thank you!

Calculus I assume?
Length*Width= 625
fencelenght= 2L + 3W
W= 625/L
fencelength= 2L+ 3*625/L
d fl/dl= 0=2 3*625/L^2
or L= sqrt (3/2 * 625)
and W= 625/sqrt (3/2 625)
Now, if you are in algebra, I don't see any way of working this except graphing
fencelength=2L 325/L and looking for the minimum. 
The local city council want to build a bike path around a square park. The park has an area of 9 square miles. How many miles long will the bike path be