Friday

January 30, 2015

January 30, 2015

Posted by **kayla** on Monday, December 1, 2008 at 3:50pm.

3^(x^3)=9^x

2^x=10

(4^x)-(2^x)=0

- precalculus -
**Reiny**, Monday, December 1, 2008 at 4:21pmfor the first you don't even need logs

3^(x^3)=9^x

3^(x^3)=(3^2)^x

3^(x^3) = 3^(2x)

so x^3 = 2x

x^3 - 2x = 0

x(x^2 - 2) = 0

x = 0 or x = ±√2

for second, take logs of both sides

log(2^x) = log 10

xlog2 = 1

x = 1/log2

for the last

4^x = 2^x

2^(2x) = 2^x

2x = x

x = 0

**Answer this Question**

**Related Questions**

Precalculus - Consider the equation 7sin^2x - (4sin2^x)/cosx = -1 a) Put the ...

Precalculus - Identify the graph of the equation. What is the angle of rotation ...

PreCalculus - y^2/25-x^2/9=0 What is the polar equation that is equivalent to ...

math algebra 1 - There are 4 times as many nickels as dimes in a coin bag. The ...

precalculus - When asked to sketch the graph of g(x)= -e^(x+1) +1, how do I ...

Algebra-Please help me - Could you please show me how to solvethis: x+6/4x^2 + 3...

SS7R - HW Question Help! - In my other post I wrote "I'm have other 3 that I ...

Precalculus - Find the equation of the ellipse with the center at (2,-3), one ...

Precalculus - Solve the equation (x+3)(x-3) = -9. What are the solutions to the ...

cananyone solvethis math - A subset S of {1,2,…,n} is said to be packed if ...