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March 28, 2015

March 28, 2015

Posted by **Joanne** on Monday, December 1, 2008 at 5:57am.

First sort... 157,225,248,271,310,337,388,451.

the minimum = 157

the minimum = =271

the median = (271+310)/2= 290.5

the upper quartile=

can you please tell me if this problem is done correctly please. also having a problem with next equation can you please help me? Multiply. (4)(-3/2 ).

- Math -
**PsyDAG**, Monday, December 1, 2008 at 9:58amYou can't have two minimums and 271 is not the maximum. Revise.

Upper quartile is (337 + 388)/2.

(4)(-3/2 ) = -12/2 = -6

I hope this helps. Thanks for asking.

- Math -
**Joanne**, Monday, December 1, 2008 at 1:16pmFind the five-number summary of the following set of numbers. 337, 248, 157, 388, 248, 451, 271, 225, 310

First sort... 157,225,248,271,310,337,388,451.

the minimum =157

the maximum = 628

the median=(271+310)/2=290.5

Upper quartile is (337 + 388)/2. = 337.5

Iam still confused can anyone help with the proccess please

- Math -
**Classified**, Tuesday, March 31, 2009 at 8:07pmMinimum = 157

Q1 = 236.5 because 236.5 is ½ way between the Minimum and the Median

Median = 271 because 271 is ½ way between the Minimum and the Maximum

Q3 = 362.5 because 362.5 is ½ way between the Maximum and the Median

Maximum = 451

**Answer this Question**

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