Saturday

September 20, 2014

September 20, 2014

Posted by **Sara** on Monday, December 1, 2008 at 1:23am.

I'm not even sure how to start this. Can someone please help me?

- Physics - please, I really need this -
**drwls**, Monday, December 1, 2008 at 2:16amYou get an upright (virtual) image if the magnification is a negative number. The magnification is the ratio of the image distance si to the object distance so. The lens equation says that

1/so + 1/si = 1/f

If f is negative and so is positive, si must be negative. Therefore si/so must be negative also.

- Physics - please, I really need this -
**Sara**, Monday, December 1, 2008 at 2:33amokay, but I'm not sure how that explains it algebraicall, could you please elaborate?

- Physics - please, I really need this -
**drwls**, Monday, December 1, 2008 at 9:14amIf 1/f is negative (as it is for a diverging lens), both so and si cannot be positive. That is the best is can do with the algebra.

You are restricted to positive values so (the object distance) with the source in front of the lens.

**Answer this Question**

**Related Questions**

Physics - Show mathematically that a diverging lens will alway produce an ...

Physics - An object is placed 30mm in front of a lens. An image of the object is...

Physical Science - Need help please. the once with the ( ) is my answer but i am...

Physics - A lamp 10 cm high is placed 60cm in front of a diverging lens of focal...

Physics - (a) A 2.20 cm high insect is 1.24 m from a 135 mm focal-length lens. ...

Physics - i have a question on thin lens equation how do i know when di is ...

physics - A converging lens (f1 = 24.0 cm) is located 56.0 cm to the left of a ...

Physics - An apple is placed 17.0 cm in front of a diverging lens with a focal ...

physics - An apple is placed 17.0 cm in front of a diverging lens with a focal ...

Physics - A converging lens (f = 14.6 cm) is located 39.0 cm to the left of a ...