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December 20, 2014

December 20, 2014

Posted by **Sara** on Monday, December 1, 2008 at 1:23am.

I'm not even sure how to start this. Can someone please help me?

- Physics - please, I really need this -
**drwls**, Monday, December 1, 2008 at 2:16amYou get an upright (virtual) image if the magnification is a negative number. The magnification is the ratio of the image distance si to the object distance so. The lens equation says that

1/so + 1/si = 1/f

If f is negative and so is positive, si must be negative. Therefore si/so must be negative also.

- Physics - please, I really need this -
**Sara**, Monday, December 1, 2008 at 2:33amokay, but I'm not sure how that explains it algebraicall, could you please elaborate?

- Physics - please, I really need this -
**drwls**, Monday, December 1, 2008 at 9:14amIf 1/f is negative (as it is for a diverging lens), both so and si cannot be positive. That is the best is can do with the algebra.

You are restricted to positive values so (the object distance) with the source in front of the lens.

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