Express in terms of logarithms of a, b, and c: log(a^3b^2)/c
How would I convert this?
log(a^3b^2)/c
= log a^3 + log b^2 - logx
= 3log a + 2log b - log c
recall log(AB) = logA + logB and
log (A/B) = logA - logB
Okay thanks
To express the expression log(a^3b^2)/c in terms of logarithms of a, b, and c, we can use the properties of logarithms.
First, let's use the power rule, which states that log(base a) (x^y) = y * log(base a) (x).
Applying this rule to the numerator of the expression, we have:
log(a^3b^2) = 3 * log(a) + 2 * log(b)
Now, let's substitute this back into the original expression:
log(a^3b^2)/c = (3 * log(a) + 2 * log(b))/c
Therefore, the expression log(a^3b^2)/c is expressed in terms of logarithms of a, b, and c as (3 * log(a) + 2 * log(b))/c.