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December 18, 2014

December 18, 2014

Posted by **Kelly** on Sunday, November 30, 2008 at 11:07pm.

- Math -
**Reiny**, Monday, December 1, 2008 at 1:04amlet the number of gallons to go into the moped be x.

let the number of gallons for the car be 12-x

restrictions:

x<=3 and 12-x <=10

x<=3 and x>=2

distance he can go by moped is 100x miles

distance he an go by car is 20(12-x) = 240 - 20x

so the total distance he can go is 80x+240 miles

but the largest x we can have is x=3

so he can go 80*3+240 = 480 miles

this of course is the distance he can go using only the 12 gallons, it doesn't say how much gas there was in the car to begin with.

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