Posted by Shawn on Sunday, November 30, 2008 at 10:24pm.
I must admit I'm not sure what you are doing but if I converted
4^-3 = 1/64 to a log equation, I would write
-3*log 4 = log(1/64).
I don't know what your answer means as
log4 1/64 = -3 since the 1/64 is just dangling out there by itself with nothing to tell me what you want to do with it.
and for 144^1/2 = 12 I would write
1/2*log 144 = log 12
By the way, when you post problems, be careful that the NUMBER of the problem doesn't run into the problem. For example, the first problem I kept reading as 10.4^-3 = 1/64
Thanks.
I have a question the formula that I used was b^y=x means that logbx=y
is this the correct formula?
so using that formula I got the following.
4^-3 =1/64 I have the answer as log4 1/64 =-3
144^1/2 =12 I have the answer as
log 144^12 =1/2
yes, you are right
if b^{y} = x then log_{b}x = y
that is the basic definition of a logarithm
So then are these answers right?
10.) 4^-3 =1/64 I have the answer as log4 1/64 =-3
11.) 144^1/2 =12 I have the answer as
log 144^12 =1/2
I don't like the way you wrote it as
log 144^12 =1/2
the ^ we use as an exponent sign, there is no exponent involved
should have been
log_{144} 12 = 1/2