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January 31, 2015

January 31, 2015

Posted by **Shawn** on Sunday, November 30, 2008 at 10:24pm.

10. 4^-3 =1/64 I have the answer as log4 1/64 =-3

11. 144^1/2 =12 I have the answer as

log 144^12 =1/2

Are these answers right?

- Algebra check -
**DrBob222**, Sunday, November 30, 2008 at 11:11pmI must admit I'm not sure what you are doing but if I converted

4^-3 = 1/64 to a log equation, I would write

-3*log 4 = log(1/64).

I don't know what your answer means as

log4 1/64 = -3 since the 1/64 is just dangling out there by itself with nothing to tell me what you want to do with it.

and for 144^1/2 = 12 I would write

1/2*log 144 = log 12

By the way, when you post problems, be careful that the NUMBER of the problem doesn't run into the problem. For example, the first problem I kept reading as 10.4^-3 = 1/64

- Algebra check -
**Shawn**, Sunday, November 30, 2008 at 11:54pmThanks.

- Algebra check DrBob222 -
**Shawn**, Monday, December 1, 2008 at 12:08amI have a question the formula that I used was b^y=x means that logbx=y

is this the correct formula?

so using that formula I got the following.

4^-3 =1/64 I have the answer as log4 1/64 =-3

144^1/2 =12 I have the answer as

log 144^12 =1/2

- Algebra check DrBob222 -
**Reiny**, Monday, December 1, 2008 at 12:41amyes, you are right

if b^{y}= x then log_{b}x = y

that is the basic definition of a logarithm

- Algebra check DrBob222 -
- Algebra check Reiny -
**Shawn**, Monday, December 1, 2008 at 12:50amSo then are these answers right?

10.) 4^-3 =1/64 I have the answer as log4 1/64 =-3

11.) 144^1/2 =12 I have the answer as

log 144^12 =1/2

- Algebra check Reiny -
**Reiny**, Monday, December 1, 2008 at 1:10amI don't like the way you wrote it as

log 144^12 =1/2

the ^ we use as an exponent sign, there is no exponent involved

should have been

log_{144}12 = 1/2

- Algebra check Reiny -

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