Posted by **Rachelle** on Sunday, November 30, 2008 at 10:07pm.

What pressure would have to be applied to steam at 325°C to condense the steam to liquid water (ÄH vap = 40.7 kJ/mol)?

Responses

Dr bob please! Chemistry - GK, Friday, November 28, 2008 at 11:47pm

Use the Clausius-Clapeyron Equation to calculate the vapor pressure at 325°C. That is the pressure that must be applied to condense the steam at 325°C.

Ln(P2/P1) = (∆H/R)[(T2-T1)/T2T1]

P1 = 1 atm

∆H = 40700J

R = 8.3145 J/°K.mol

T2 = (325+273) = 598°K

T1 = (100+273) = 373°K

P2 = (unknown)

[NOTE: The pressure needed is quite high]

Dr bob please! Chemistry - Rachelle, Sunday, November 30, 2008 at 10:06pm

i solved for lnx=4,852,725

whats next? and i relaly cant put it into the calc. it says (overflow)

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