math
posted by heidi on .
Solve the following matrices (I don't know how to do brackets so I will just use commas to separate the numbers and put them in different lines)
A= 0, 2, 3, 1
3, 1, 0, 4
0, 5, 2, 1
B= 1, 4
2, 1
3, 0
C= 1, 0, 2
0, 3, 4
0, 8, 1
E= 1
2
3
4
F= 2, 5
3, 7
0, 9
FIND:
) AE =
b) B+F =
c) BC + F =
d) CB =
e) CC =

AE =
top row 0*1 2*2+3*3+1*4 = 9
row two 3*1+1*2+0*3+4*4 = 15
row three 0*1+5*22*31*4 = 0
B+F = S
S11 = 12 = 1
S12 = 5+5 = 1
S21 = 2+3 = 1
S22 = 1+7 = 8
S31 = 3+0 = 3
S32 = 0+9 = 9
so Sum is
1 , 1
1 , 8
3 , 9
First do BC, then add F
B has two columns, C has three rows
so you may not multiply B times C
(C times B would be ok)
ok, now CB = P
P11 = 1*1+0*2+2*3 = 5
P12 = 1*4+0*1+2*0 = 4
P21 = 0*1+3*2+4*3 = 6
P22 = 0*4+3*1+4*0 = 3
P31 = 0*1+8*21*3 = 19
P33 = 0*4 +8*11*0 = 8
so CB=
5 , 4
6 , 3
19 , 8
CC
1 , 16 , 4
0 , 41 , 8
0 , 16 , 33 
kjihgo zsmv ambno pqezmnxc xnsrat ndcofb aoxzqwjlf