Chem. Find specific heat capacity.
posted by Sarah on .
A piece of lead with a mass of 27.3 g was heated to 98.90oC and then dropped into 15,0 g of water at 22.50oC. The final temperature was 26.32oC. Calculate the specific heat capacity of lead from these data.
THANK YOU FOR ANY HELP!
[massPb x specific heat Pb x (Tfinal-Tinitial)] + [massH2O x specific heat H2O x (Tfinal-Tinitial)] = 0
Only one unknown; i.e., specific heat Pb. Solve for that. Post your work if you get stuck.
This is what I did. Could you check my answer? I would really appreciate it.
q = mcÎ”t
-mcÎ”t = mcÎ”t
clead = .121
You are right.