Posted by **helpme** on Sunday, November 30, 2008 at 7:53pm.

Mrs. Brighton invested $30,000 and received a total of $2,300 in interest. If she invested part of the money at 10% and the remainder at 5%, then how much did she invest at each rate?

- math -
**Damon**, Sunday, November 30, 2008 at 7:57pm
.10 x + .05 (30,000-x) = 2,300

10 x + 5 (30,000-x)= 230,000

2 x + (30,000 - x ) = 46,000

x + 30,000 = 46,000

you take it from there

- math -
**drwls**, Sunday, November 30, 2008 at 8:00pm
Assume that the money was left on deposit for one year. They should have told you that.

If x was invested at 10%, 30,000- x was invested at 5%

x * 0.10 + (30,000 -x) * 0.05 = 2300

0.1 x + 1500 - .05x = 2300

0.05 x = 800

x = 16,000 (invested at 10%)

(30,000 - x) = 14,000 invested at 5%

## Answer This Question

## Related Questions

- math - Different Interest Rates. Mrs. Brighton invested $30,000 and received a ...
- Algebra - 4x-5y=-2 3y-x=-3 4x+5y=-2 4y-x=11 3x-6y=5 2y=4x-6 2x+y=9 2x-5x=15 3y-x...
- business - Donna invested her $33,000 bonus and received a total of $970 in ...
- math - Mr Joyce invested $ 25,000, part at 4% interest and the remainder at 7% ...
- Math Help Please - Bob invested $30,000, part at 10% and part at 1%. If the ...
- algebra - Janet invested $23,000, part at 6% and part at 17%. If the total ...
- Word Problem - Can someone help me figure out the equation? I am not good at ...
- algebra - A total of $12,000 is invested in two funds paying 9% and 11% simple ...
- algebra - two investments were made totaling $15,000. for a certain year these ...
- Algebra - I invested $42,000 in three funds paying 5%, 7%, and 9% simple ...

More Related Questions