Posted by **helpme** on Sunday, November 30, 2008 at 7:53pm.

Mrs. Brighton invested $30,000 and received a total of $2,300 in interest. If she invested part of the money at 10% and the remainder at 5%, then how much did she invest at each rate?

- math -
**Damon**, Sunday, November 30, 2008 at 7:57pm
.10 x + .05 (30,000-x) = 2,300

10 x + 5 (30,000-x)= 230,000

2 x + (30,000 - x ) = 46,000

x + 30,000 = 46,000

you take it from there

- math -
**drwls**, Sunday, November 30, 2008 at 8:00pm
Assume that the money was left on deposit for one year. They should have told you that.

If x was invested at 10%, 30,000- x was invested at 5%

x * 0.10 + (30,000 -x) * 0.05 = 2300

0.1 x + 1500 - .05x = 2300

0.05 x = 800

x = 16,000 (invested at 10%)

(30,000 - x) = 14,000 invested at 5%

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