Posted by Chelsi on Sunday, November 30, 2008 at 7:23pm.
How do you factor 3x^3+81

Math  drwls, Sunday, November 30, 2008 at 7:30pm
Call it 3(x^3 + 27).
27 is the cube of three, so one root is x = 3 and the corresponding factor is (x+3). For the other factor, use syntheic division to compute
(x^3+27)/(x+3). That turns out to be
(x^2 3x + 9). The other roots are complex, so leave it as
3x^3 + 81 = 3(x+3)(x^2 3x + 9)
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