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Posted by on Sunday, November 30, 2008 at 6:58pm.

Find the derivative of f(x) = x^2 ln (x^2) using the Product Rule, and simplify.

  • Calculus - , Sunday, November 30, 2008 at 7:37pm

    Let x^2 = u and ln(x^2) = 2 ln x = v

    f'(x) = u dv/dx + v du/dx
    f'(x) = x^2*(2/x) + 2x *2 ln x)
    = 2x + 4 x ln x = 2 x (ln x + 1)

  • Calculus - , Sunday, November 30, 2008 at 7:41pm

    y = (x^2) ln(x^2)
    but ln(x^2) = 2 ln x
    so
    y = 2(x^2)ln x
    dy/dx = 2(x^2) dy/dx (ln(x)) + 2 ln(x)dy/dx(x^2)

    = 2 x^2 (1/x) + 2 ln x (2 x)
    =2x +4x ln x
    =2x(1+2lnx)

  • Calculus - , Sunday, November 30, 2008 at 7:51pm

    My last equation was wrong. Damon is right

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