Posted by **cindy** on Sunday, November 30, 2008 at 4:12pm.

A brick weighs 15.0 N and is resting on the ground. Its dimensions are 0.203 m multiplied by 0.0890 m multiplied by 0.0570 m. A number of the bricks are then stacked on top of this one. What is the smallest number of whole bricks (including the one on the ground) that could be used, so that their weight creates a pressure of at least one atmosphere on the ground beneath the first brick? (Hint: First decide which face of the brick is in contact with the ground.)

## Answer This Question

## Related Questions

- Physics - A brick weighs 15.0 N and is resting on the ground. Its dimensions are...
- physics - A brick weight 17.8N and is resting on the ground. Its dimensions are ...
- general physics - A solid concrete block weighs 160 N and is resting on the ...
- Physics - Four bricks are to be stacked at the edge of a table, each brick ...
- physics -- fluid mechanics - Neutron stars consist only of neutrons and have ...
- math - bricks are stacked in 20 rows such that each row has a fixed number of ...
- geometry - Square is the product of a number multiplied with that number itself....
- physics - there are 1000 bricks and when they are stacked neatly they measure 2m...
- ***Chemistry!!!! - Carry out the following operations, and express the answer ...
- maths - A brick wall is built by using 2 bricks less in each layer than in the ...

More Related Questions