A brick weighs 15.0 N and is resting on the ground. Its dimensions are 0.203 m multiplied by 0.0890 m multiplied by 0.0570 m. A number of the bricks are then stacked on top of this one. What is the smallest number of whole bricks (including the one on the ground) that could be used, so that their weight creates a pressure of at least one atmosphere on the ground beneath the first brick? (Hint: First decide which face of the brick is in contact with the ground.)
1 atm= 101.3 Kilo newton/m^2
pressure= Number*15/area (decide which area, I recommend the smallest side down).
101.3*10^3*area/15 = number bricks.
To find the smallest number of whole bricks required to create a pressure of at least one atmosphere on the ground beneath the first brick, we need to calculate the total weight of the bricks.
The weight of the first brick is given as 15.0 N. The pressure exerted by an object is given by the formula:
pressure = force / area
Assuming the contact area of the brick in contact with the ground is the bottom face, the area is:
area = length x width = 0.203 m x 0.0890 m = 0.018127 m^2
Now, let's calculate the pressure exerted by the first brick:
pressure = 15.0 N / 0.018127 m^2
Next, we'll convert the pressure to atmospheres. 1 atmosphere is equal to 101325 Pascals (Pa). Therefore:
pressure_atm = pressure / 101325
The number of whole bricks required can be determined by dividing the pressure requirement of 1 atmosphere by the pressure exerted by a single brick:
number_of_bricks = 1 atm / pressure_atm
Finally, round up the value to the nearest whole number to get the smallest number of whole bricks required.
Note: To use this formula, we assume that the weight of the bricks is evenly distributed, and there are no other resistive forces in play.
By following these steps, you should be able to determine the smallest number of whole bricks needed to create a pressure of at least one atmosphere on the ground beneath the first brick.