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December 18, 2014

December 18, 2014

Posted by **tina** on Sunday, November 30, 2008 at 3:45pm.

------------ m from the 490 kg mass

I do not understand how to attack this problem. pls help.

- physics -
**Damon**, Sunday, November 30, 2008 at 3:50pmcall our mass m, the 35 does not matter, could be any amount.

we are x meters from the 190 kg

and

we are (0.4 - x) meters from the 490 kg

we have to be on the line between them so we are not pulled sideways

so

Fleft = G(190)m /x^2

Fright = G(490)m/(.4-x)^2

so for equal and opposite

190/x^2 = 490/(.4-x)^2

solve the resulting quadratic for x

- physics -
**tina**, Sunday, November 30, 2008 at 3:59pmwhen i try and solve this i get 300x^2+152x-30.4

how would i solve after this?

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