Posted by tina on Sunday, November 30, 2008 at 3:45pm.
call our mass m, the 35 does not matter, could be any amount.
we are x meters from the 190 kg
and
we are (0.4 - x) meters from the 490 kg
we have to be on the line between them so we are not pulled sideways
so
Fleft = G(190)m /x^2
Fright = G(490)m/(.4-x)^2
so for equal and opposite
190/x^2 = 490/(.4-x)^2
solve the resulting quadratic for x
when i try and solve this i get 300x^2+152x-30.4
how would i solve after this?
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