Sunday

March 1, 2015

March 1, 2015

Posted by **Mary** on Sunday, November 30, 2008 at 12:09pm.

- calculus -
**Reiny**, Sunday, November 30, 2008 at 12:37pmlet the radius of the can be r mm

and its height be h mm

area = 1 rectangle + 2 circles

= 2pi(r)(h) + 2pi(r^2)

seems length = 2 circuferences + height of can

= 2(2pi(r)) + h

= 4pi(r) + h

so Cost = 2[2pi(r)(h) + 2pi(r^2)] + 1[4pi(r) + h]

but pi(r^2)h = 1000

so h = 1000/(pi(r^2))

this should give you a good start, sub h back into the Cost equation,

find the derivative of Cost,

then solve for r

sub back into Cost equation to find minimum cost

**Answer this Question**

**Related Questions**

Word Problem Cost minimization - Don Garcia needs at least 24 units of vitamin A...

calculus - a rectangular box is to have a square base and a volume of 20 ft ...

Math - A can of worms for fishing costs $2.60. There are 20 worms in a can. What...

Calculus,math - Constuct a rectangular box with a square base that holds a given...

Math - A manufacturer produces certain devices. The fixed cost of production is...

Pre-Calculus - A local photocopying store advertises as follows. " We charge 14 ...

math - Formerly 1/6 of a pie cost 20 cents.Now the price of 1/8 of a pie is 30 ...

marketing - QUESTION #1 cost analysis with graph office copier has an initial ...

Business Calculus - A manufacturer has found that marginal cost is dc/dx=3x^2-...

Math- Linear Programming - A dog food is to be mixed from three kinds of ...