Posted by Joey on .
Hi I am absolutely stumped on this question.
A loudspeaker is placed between two observers who are 110 m apart, along the line connecting them. If one observer records a sound level of 60.1 dB and the other records a sound level of 74.9 dB, how far is the speaker from each observer?
What I did for this is
I found the the Intensities of both the sound levels.
Then using the formula r1= SQRT(I2/I1)*R2
I would solve for r1 and then do r1+r2=113 to find r2.
I also don't know what value to assign for I2 and I1, i tried both ways but its wrong.
Please Help!
Thanks In Advance

Physics 
drwls,
This is the fourth time you have posted this question, which has already been answered. Please stop

Physics 
drwls,
There was a typo error in my previous answer, which you noticed. The final answer is the same.
In calculating the intensity ratio, I meant to write 10^1.48 = 30.2. Sorry about the typo in the exponent. The 30.2 is correct. 1.48 is 1/10 of the dB difference in received sound levels.
If it is a mystery where the 10^(0.1*dB difference)comes from, that is the definition of decibels in terms of intensity ratio
Log10(I2/I1) = 1/10 (dB2  dB1)
10^[0.1(dB2dB1)] = I2/I1