Math please help...younger brother needs help
posted by Saira on .
1.HOW do you state the amplitude, period, phase shift and vertical shift for the function y= 2sin[4(angle symbol)pie/2]5?
2. Describe the function y= 5sin4 (angle symbol+30degrees)4 as a transformation of the function y= sin(angle).

1. The amplitude is 2.
Since time does not appear in the equation, I cannot say what the period is.
The phase shift is pi/2
The vertical shift is 5
2. The function y= 5sin4 (angle symbol+30degrees)4
has five times the amplitude of y= sin(angle).
It is also shifted vertically by 4, and has a phase shoft of 30 degrees. 
Allow me to make a small correction to drwls solution.
in 1. the equation was given as
y= 2sin[4(angle symbol)pie/2]5
to read the phase shift directly from the equation the factor of 4 should be outside the bracket, so change it to
y= 2sin4[(angle symbol)pie/8]5
and now the phase shift is pi/8 to the right.
The period is 2pi/k for y = asink(theta)
so here the period is 2pi/4 or pi/2