Tuesday

September 30, 2014

September 30, 2014

Posted by **steve alexander** on Tuesday, November 25, 2008 at 7:45pm.

1.-calculate the estimate population in 12 years

2.-when the population increases 4 times

could somebody please explain me this kind of problems where you need to use the log and please tell me the answers

- precalculus -
**Craig**, Tuesday, November 25, 2008 at 7:59pm1. .015*65*12+65=76.7 million

2. 4*65=260 million

- precalculus -
**drwls**, Tuesday, November 25, 2008 at 8:03pm1. Multiply 65 million by (1.015)^12

(1.015^12 = 1.1956)

2. Multiply 65 million by 4.

You don't need to use log for the second one.

You can to 1. with a log table or with a hand calculator (as I did).

If you use logs:

Log (answer) = log (65 million) + 12 log 1.015

Then take the antilog

You will learn more if you do the calculations yourself than if I gave you the numerical answers.

- precalculus -
**North**, Sunday, November 30, 2008 at 3:09amLet

P = population in millions

t = time in years

Population growth is continuous. For continuous compounding use the formula:

P = 65*e^(.015t)

For the population in 12 years we have:

P = 65*e^(.015*12) = 65*e^(.18)

P = 77.8 million

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