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February 1, 2015

February 1, 2015

Posted by **jane** on Tuesday, November 25, 2008 at 5:21pm.

a) find the slope of the tangent to the graph of f at a general point x0 using the definition of the dervative.

b) use the result in part a to find the slope of the tangent at x0=1.

I am very confused.

My answer for (a) 1/ 6-6x-x^2

(b) -1

I compared them to a classmate - answers didnt agree.

I am lost.

- HS Calculus -
**Reiny**, Tuesday, November 25, 2008 at 5:27pmHow did you get that derivative?

I rewrote the equation to

y = 2(3-x)^-1

then y' = -2(3-x)^-2(-1)

= 2/(3-x)^2 or 2/(x^2 - 6x + 9)

so when x=1, y' = 2/(3-1)^2 = 1/2

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