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November 28, 2014

November 28, 2014

Posted by **george** on Tuesday, November 25, 2008 at 1:56am.

- calculus -
**drwls**, Tuesday, November 25, 2008 at 2:20amIf you cut out corner squares with length x , the height of the box is x and the base dimensions are (12-2x) * (16 - 2x)

Box volume V = x(12-2x)(16-2x)

(0 < x < 6)

V = 192x -56x^2 + 4x^3

Set the derivative dV/dx = 0 and solve for x

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