Homework Help: physics

Posted by Sandhya on Tuesday, November 25, 2008 at 1:40am.

A bungee jumper with mass 69.5 kg jumps from a high bridge.
After reaching his lowest point, he oscillates up and down,
hitting a low point eight more times in 36.6 s. He finally
comes to rest 24.3 m below the level of the bridge. Calculate
the spring constant of the bungee cord.

physics - drwls, Tuesday, November 25, 2008 at 2:03am
The frequency is 8/36.6 = 0.2185 Hz

That equals [1/(2 pi)]sqrt(k/m)

You know m = 69.5 kg. Solve for k

The 24.3 m number you do not need.
physics - Sandhya, Tuesday, November 25, 2008 at 8:42am
Thanks for the timely help

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