Math
posted by Jay111 on .
The critical numbers of the function:
f(t)=7t^(2/3)+t^(5/3)
f'(t)=14/3t^(1/3)+(5/3)t^(2/3)
I got 0 as a critical number but it is hard for me to factor the f'(t). Whats the other critical number? Thank you.

If 14/3t^(1/3)+(5/3)t^(2/3)= 0, then
t^(1/3) [14/3 + (5/3)t] = 0
t = 0 or 14/5