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October 1, 2014

October 1, 2014

Posted by **Jay111** on Monday, November 24, 2008 at 11:47pm.

f(t)=7t^(2/3)+t^(5/3)

f'(t)=14/3t^(-1/3)+(5/3)t^(2/3)

I got 0 as a critical number but it is hard for me to factor the f'(t). Whats the other critical number? Thank you.

- Math -
**drwls**, Monday, November 24, 2008 at 11:52pmIf 14/3t^(-1/3)+(5/3)t^(2/3)= 0, then

t^(-1/3) [14/3 + (5/3)t] = 0

t = 0 or -14/5

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