Posted by **Tracy** on Monday, November 24, 2008 at 4:10pm.

Cheryl gave Brenda 7 coins worth .92 cents. Two coins were quarters. What were the other 5 coins?

- Math -
**DrBob222**, Monday, November 24, 2008 at 4:22pm
Probably there are equations that can be set up but you can also do it by logic.

2 coins are 0.25 = 50 cents. That leaves 92-50 = 42 cents and 5 coins to go.

The only way to get 2 cents is to have 2 pennies. That leaves 40 cents and 3 coins to go.

The only way to get 40 cents with 3 coins is 1 quarter, 1 dime, and 1 nickel.

So you have 3 quarters = 75 cents.

2 pennies = 2 cents.

1 dime = 10 cents.

1 nickel = 5 cents.

92 cents total and 7 coins.

The only way to get 40 cents

## Answer this Question

## Related Questions

- 5th grade math - I need to use quarters, dimes, nickles and pennies to make the ...
- Math problem I need help with - Combination of coins that can be used; fifty-...
- math - Three coins are selected from 10 coins: 4 dimes, 4 nickels, and 2 ...
- Math - There are 52 coins that consists of pennies, dimes, and quarters. Two ...
- Math - Julian has 10 coins. Sue has 5 coins. There is a total of 4 quarters. Sue...
- Math - Susan has some $2-coins and $5-coins. If there are 18 coins and the total...
- Math - Shirley has 18 coins. One sixth of the coins are quarters, one third of ...
- maths ...(HELP) - i really do not get this question bacuse i dont get what it ...
- maths - A bag contained a number of 20cents, 50cents and $1 coins. 1/3 of the ...
- Math - Select three (3) coins, but assume that there are 4 dimes, 4 nickels, and...

More Related Questions