Posted by Kiki on Monday, November 24, 2008 at 1:01am.
In the function f(x)=(x+5)^4 +k , for which values of k does the function have two real solutions? no real solutions? Explain?

math  drwls, Monday, November 24, 2008 at 4:01am
Your f(x)=(x+5)^4 +k expression
defines what f(x) is, but does not have a "solution" per se. No matter what value of k one chooses, if you pick an x, one can compute an f(x).
Something has been omitted from your question that needs to be there. Perhaps they are lookig for "solutions" to f(x) = 0. If so, the question should have said so.
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