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July 29, 2014

July 29, 2014

Posted by **Kiki** on Monday, November 24, 2008 at 1:01am.

- math -
**drwls**, Monday, November 24, 2008 at 4:01amYour f(x)=(x+5)^4 +k expression

defines what f(x) is, but does not have a "solution" per se. No matter what value of k one chooses, if you pick an x, one can compute an f(x).

Something has been omitted from your question that needs to be there. Perhaps they are lookig for "solutions" to f(x) = 0. If so, the question should have said so.

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