Posted by **Kiki** on Monday, November 24, 2008 at 1:01am.

In the function f(x)=(x+5)^4 +k , for which values of k does the function have two real solutions? no real solutions? Explain?

- math -
**drwls**, Monday, November 24, 2008 at 4:01am
Your f(x)=(x+5)^4 +k expression

defines what f(x) is, but does not have a "solution" per se. No matter what value of k one chooses, if you pick an x, one can compute an f(x).

Something has been omitted from your question that needs to be there. Perhaps they are lookig for "solutions" to f(x) = 0. If so, the question should have said so.

## Answer this Question

## Related Questions

- algebra 2 - In the function f(x)=(x+5)^4 +k , for which values of k does the ...
- algebra - determine the nature of the solutions of the equation, one real ...
- Math - How many real number solutions does the equation have? y=3x^2-5x-5 A)one ...
- Math - 1)How many real number solutions does the equation have? -8x^2-8x-2=0 A) ...
- Math - For the following equation, state the value of the discriminant and then ...
- algebra - determine the nature of the solutions of the equation. Two real ...
- Algebra - For the following equation, state the value of the discriminant and ...
- math - how many real number solutions does the equation have y = -4x^2 + 7x - 8 ...
- Algebra - in x^2+14=0, how many solutions do we have? A)2 real solutions B)1 ...
- Math - I am given 4 choices for the problem the square root of 8x -2 = the ...

More Related Questions