Posted by **stephanie** on Sunday, November 23, 2008 at 10:32pm.

a particle starts at time t=0 and moves on a number line so that its position at time t is given by x(t)= (t-2)^3(t-6)

what is the farthest to the left of the origin that hte particles moves??

i was able to find the velocity and acceleration formula. but i have no idea how to do this

## Answer This Question

## Related Questions

- AP CALC. AB - 1.The position of a particle moving on the line y = 2 is given by ...
- Calc - A particle moves along the x-axis in such a way that it's position in ...
- Calc - A particle moves along the x-axis in such a way that it's position in ...
- Calculous - A particle moves along the c-axis so that at time t its position is ...
- Calculus - a particle starts at time t = 0 and moves along the x axis so that ...
- Calculus-particle motion - 1. A particle is moving on the x-axis (or any number ...
- calculus - a particle moves along a number line measured in cm so that its ...
- Calculus!!!! - A particle moves along the x-axis with position at time t given ...
- Calculus - A particle moves along the x-axis with position at time t given by x(...
- Calculus - A particle moves along the x-axis with position at time t given by x(...

More Related Questions