Posted by **Kim** on Sunday, November 23, 2008 at 3:08pm.

How to solve this: 5/a=?/a to the second power

- Algabra -
**Kim**, Sunday, November 23, 2008 at 3:16pm
I forgot to put this in the question i asked. Here it is again. 5/a=?/a 2power

Write an equivenlant expression to this.

- Algabra -
**elvin**, Thursday, December 11, 2008 at 2:22am
x times x =?

- Algabra -
**Jeremy**, Sunday, November 23, 2008 at 3:49pm
5/a=?/a^2

5a^2=a?

5=(a?)/a^2

5=?/a or 5a=? or a=?/5

If that's what your question is asking for, I hope that helps.

- Algabra -
**eliana**, Friday, December 12, 2008 at 3:27pm
4x-4-6x+x-17=3

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