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September 1, 2014

September 1, 2014

Posted by **slayer** on Sunday, November 23, 2008 at 10:14am.

2.)A horizontal segment of pipe tapers from a cross-sectional area of 50 cm^2 to 0.5 cm^2. The pressure at the larger end of the pipe is 1.2x 10^5 Pa and the speed is 0.04m/sec. What is the pressure at the narrow end of the segment?

- physics -
**drwls**, Sunday, November 23, 2008 at 10:44am1. time = Volume / (volume flow rate)

= V/(area*velocity)

2. Because of the continuity equation, V*Area = constant. Use that fact to get the narrow-end velocity. Then apply the Bernoulli equation for the pressure change.

Someone will be glad to critique your work

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