Posted by Akitsuke on Saturday, November 22, 2008 at 10:02pm.
1. Volume flow rate = (Area)(Velocity) = pi*2^2/4 V = pi cm^2* 35 cm/s = 110 cm^3/s
Amount filled = V = 10,000 cm^3 = Q t
t = V/Q = 10,000 cm^2/(110 cm^3/s)
= ? s
2. Use the incompressible continuity equation V*A = constant to get the velocity at the narroqw end. Velocity will be 100 times higher at the narrow end. Then apply Bernoulli's equation for the pressure change.
P + (1/2)*(density)*V^2 = constant
P2 - P1 = (1/2)(density)(V1^2 - V2^2)
thanks for your help. :)
Related Questions
physics - 1.)Water flows from a 2 cm diameter pipe, at a speed of 0.35m/sec. How...
physics - 1.)Water flows from a 2 cm diameter pipe, at a speed of 0.35m/sec. How...
physics - 1.) Water flows from a 2 cm diameter pipe, at a speed of 0.35m/sec. ...
physics - Water flows through a 1.2 cm diameter pipe into a 155 L bathtub, which...
physics - Water flows through a 1.2 cm diameter pipe into a 155 L bathtub, which...
Physics - Water flowing through a 2.8 cm-diameter pipe can fill a 200 L bathtub ...
Physics - Water flowing through a 2.8 cm-diameter pipe can fill a 200 L bathtub ...
Physics - Water flowing through a 2.8 cm-diameter pipe can fill a 200 L bathtub ...
Physics - Water flowing through a 2.8 cm-diameter pipe can fill a 200 L bathtub ...
physic - Water flows through a 4.0-cm-diameler horizontal pipe ata speed uf 1.3 ...
For Further Reading