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October 20, 2014

October 20, 2014

Posted by **Akitsuke** on Saturday, November 22, 2008 at 10:02pm.

2.) A horizontal segment of pipe tapers from a cross-sectional area of 50 cm^2 to 0.5 cm? The pressure at the larger end of the pipe is 1.2x 10^5 Pa and the speed is 0.04m/sec. What is the pressure at the narrow end of the segment?

thanks. :)

- physics -
**drwls**, Sunday, November 23, 2008 at 6:40am1. Volume flow rate = (Area)(Velocity) = pi*2^2/4 V = pi cm^2* 35 cm/s = 110 cm^3/s

Amount filled = V = 10,000 cm^3 = Q t

t = V/Q = 10,000 cm^2/(110 cm^3/s)

= ? s

2. Use the incompressible continuity equation V*A = constant to get the velocity at the narroqw end. Velocity will be 100 times higher at the narrow end. Then apply Bernoulli's equation for the pressure change.

P + (1/2)*(density)*V^2 = constant

P2 - P1 = (1/2)(density)(V1^2 - V2^2)

- physics -
**Akitsuke**, Sunday, November 23, 2008 at 8:49amthanks for your help. :)

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