sorry the slash after the three should actually be a period, the equation is only 24t/2t+3
v(t)=24t/(2t+3) [[ Maybe ?????? ]]
Although I can't post the graph, there are two points labeled, (3,10) and (10,10).
[[ and (0,0) ]] maybe????
MAKING THOSE ASSUMPTIONS ABOUT WHAT YOU WERE GIVEN!!!!
At two seconds for runner A
I think runner A went from (0,0) to (3,10) in a straight line
y = m x + b
(0,0) ---> b = 0
m = 10/3
y = (10/3)x
for x = 2 y = 20/3 or 6.67
Runner B if y = 24 x / (2x+3)
where x = 2
y = 48 / (4+3) = 48/7 = 6.86
thank you so much! as a follow up question, for acceleration of the two runners, is acceleration the anti derivative of velocity???
thank you so much or your help! as a follow up question, for acceleration of the two runners, is acceleration the anti derivative of velocity???
acceleration = dv/dt
dv/dt for A = 10/3 (constant slope until t = 3)
dv/dt for B
a = dv/dt = [(2t+3)(24) -24t(2) ]/(2t+3)^2
put in t = 2
a(2) = dv/dt = [ 7(24)- 96 ] /(49)
= 72/49 = 1.47
By the way, position is the anti-derivative of velocity
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